Question

3S2CL2 + H2o ----> 3S +H2SO3 + 4HCL

Which product is formed by reduction and which by oxidation with explanation?

Answer 1

\[3S_2Cl_2 + H_2O ----> 3S +H_2SO_3 + 4HCl\]

Answer 2

Consider the oxidation numbers (ON).
Change
ON of S in S2Cl2 = +1 ON of S in S = 0 decrease
ON of S in H2SO3 = +4 increase
ON of Cl in S2Cl2 = -1 ON of Cl in HCl =-1 ----
ON of H in H2O = +1 ON of H in H2SO3/HCl = +1 ----
ON of O in H2O =-2 ON of O in H2SO3 = -2 ----

So, S is formed by reduction and H2SO3 is formed by oxidation

Answer 3

Ohhhh thank you!!

Answer 4

Welcome