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Find the set of values of k for which the line y=2x-5 cuts the curve y=x^2+kx+11 in two distinct points.
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b^2-4ac
y=2x-5, y=x^2+kx+11 x^2+kx+11=2x-5 x^2-2x+kx+16=0 x^2+(-2+k)x+16=0 a=1 b=-2+k c=16
b^2-4ac= (-2+k)-4(1)(16)=0 solve
Thank you very much (:
yw
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