the kentucky lottery is worth $100,000. to win you have to select the 5 winning numbers from 1-50. how many different combinations are possible?
i believe the formula would be \[\large \frac{50!}{5! 45!}\] feel free to correct me though @apoorvk
where did you get the 45?
50 - 5 i believe
Yes, it'd be 50c5 \(\Large \color{purple}{ 50! \over (50 - 5)!*5! }\)
Get it?
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nCr is represented as: \(\Large \color{purple}{ {n! \over (n - r)!*r!} }\)
n= the amount of numbers =50 r= the numbers you want so 5 50!/(50-5)!5!
no @lgbasallote I won't need to correct you. For choosing 'r' things out 'n', (arrangement not being considered), no. of possible combinations 'N': \[\large N = ^nC_r = \frac{n!}{r!(n-r)!}\]
heh i cant believe i got the formula right..i only context clues-ed from amistre's work earlier \m/
If you have to choose 5 numbers from 50, then it'll be 50 choose 5 aka 50c5
can you go from there now @catgirl17
Considering that you know what factorials are lolz
oh god please know what factorials are...
it's gonna be a long post slash night if fno
\(\Large \color{purple}{ n! = n * (n - 1) * (n - 2) * (n - 3) ........1 }\)
after 50!/45!x5! do i just expand it out
Just having some fun
yes you do @catgirl17
And then you cancel to make it simpler.
and if i were you get rid of x...you might mistake it for a variable
thank you @lgbasallote
Use * instead of x lol
\[\huge \color{maroon}{\mathtt{\text{<tips hat>}}}\]
* doesn't only represent the thing that twinkles. lol
or use ( )( ) yeah...they're more subtle
\(\Large \color{purple}{\mathbb{Still} \text{ doesn't get the medal. xP} }\)
when expanding the 50! out do i have to go all the way to 5! ?
50! =50x49x48x47......x1
wait wait... n! OVER r! = (n - r)!
50!/45! cancels out to 50x49x48x47x46 divide that by 5!
just until 45! it will cancel out anyway... \[\large \frac{50! 49! 48! 47! 46! 45!}{45! 5!}\] see? 45! will just cancel out
why have you got all those factorials on top?!
Are you kdding me? 50! is not 50! * 49!........
fine get rid of the ! :P
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