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2x/x+1= 3/x-2 + 1/ x^2-x-2
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now when doing this do I need to move things because of the = sign?
Am I reading this equation correctly? \[\frac {2x}{x+1}= \frac{3}{x-2} + \frac{1}{x^2-x-2}\]
yes, for some reason it gives me an error when i use the equation thing
well, can you factor\[x^2-x-2\]
so would it go down to just x^2 on the bottom?
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no. Do you know what I mean by factor? what values of a and b would solve this equation?\[x^2-x-2=(x+a)(x+b)\] where we know that a + b = -1 and ab = -2
We are trying to find the LCD (lowest common denominator).
|dw:1337530877435:dw|
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