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Use properties of exponents to simplify \[\left( 27m^\frac{3}{2}n^{-6} \right)^\frac{2}{3}\]
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yeah it typed correct this time
one at at time \[27^{\frac{2}{3}}=\sqrt[3]{27}^2=3^2=9\]
\[(m^{\frac{3}{2}})^{\frac{2}{3}}=m^{\frac{3}{2}\times \frac{2}{3}}=m^1=m\]\]
thye cancel each other out correct
they even
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use the power of a power law \[(x^a)^b= x^{a \times b}\] so its \[(3^3)^{\frac{2}{3}}\times (m^{\frac{3}{2}})^{\frac{2}{3}} \times (n^{-6})^{\frac{2}{3}}\]
\[(n^{-6})^{\frac{2}{3}}=n^{-6\times \frac{2}{3}}=n^{-4}=\frac{1}{n^4}\]
yes they cancel
ok i think i already asked this question, i ment to type something different, i am so sorry, do you want me to close this and ask agian?
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