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OpenStudy (anonymous):
n △PQR, find the measure of ∡P.
30.4°
59.6°
35.9°
54.1°
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OpenStudy (anonymous):
OpenStudy (anonymous):
I really need help! Thank you. =]
OpenStudy (anonymous):
are you using trigonometry with this?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
angle P- 90/sin 57.6 =33.8/sin P then cross multiply
90sinP=33.8sin57.6
divide by 90
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OpenStudy (anonymous):
then do \[\sin^{-1} \](answer)
OpenStudy (anonymous):
tip: when you're looking for your angles always use the inverse of your answer
OpenStudy (anonymous):
@mich7896 you there?
OpenStudy (anonymous):
Yeah i'm just trying to figure it out xD
OpenStudy (anonymous):
oh ok ^^' i hope i didnt make you confused. i'll explain more if needed
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OpenStudy (anonymous):
could you explain a little more? I'm still a bit confused =]
OpenStudy (anonymous):
I just started this class so i'm new to this xD
OpenStudy (anonymous):
oh ok ^^' do you know the model for the law of sine?
OpenStudy (anonymous):
i think so =]
OpenStudy (anonymous):
the law of sine is: a/sinA=b/sinB=c/sinC which basically looks like this(sorry its a little sloppy) |dw:1337554546317:dw|
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