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Mathematics 17 Online
OpenStudy (anonymous):

n △PQR, find the measure of ∡P. 30.4° 59.6° 35.9° 54.1°

OpenStudy (anonymous):

OpenStudy (anonymous):

I really need help! Thank you. =]

OpenStudy (anonymous):

are you using trigonometry with this?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

angle P- 90/sin 57.6 =33.8/sin P then cross multiply 90sinP=33.8sin57.6 divide by 90

OpenStudy (anonymous):

then do \[\sin^{-1} \](answer)

OpenStudy (anonymous):

tip: when you're looking for your angles always use the inverse of your answer

OpenStudy (anonymous):

@mich7896 you there?

OpenStudy (anonymous):

Yeah i'm just trying to figure it out xD

OpenStudy (anonymous):

oh ok ^^' i hope i didnt make you confused. i'll explain more if needed

OpenStudy (anonymous):

could you explain a little more? I'm still a bit confused =]

OpenStudy (anonymous):

I just started this class so i'm new to this xD

OpenStudy (anonymous):

oh ok ^^' do you know the model for the law of sine?

OpenStudy (anonymous):

i think so =]

OpenStudy (anonymous):

the law of sine is: a/sinA=b/sinB=c/sinC which basically looks like this(sorry its a little sloppy) |dw:1337554546317:dw|

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