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Solve "6 cos (2x) - 2 sin (x) = 4" for [0,2Pi)
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double angle identity: cos(2x) = 1-2sin^2
treat it like a quadratic equation, set equal to 0 --> 12sin^2 +2sin -2 = 0
I never thought of that! Hold on
sin x = y 12y^2 + 2y - 2 = 0 (4y + 2)(3y - 1) = 0 y = -1/2 or y = 1/3
very good, not use inverse sine to get x values
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now*
sin x = -1/2 x = -.523598 sin x = 1/3 x = .339836
Would I have to turn this into a "better looking" value? Such as pi over a number?
yes but remember x is in [0,2pi] make it positive angle also use unit circle, there should be 4 total solutions
Right, how would you go about doing that?
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for sin x = -1/2, yes its x = -pi/3 but for the other one there is no "nice" value
|dw:1337559658678:dw| find the angles
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