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prove csc2x=cscxsecx/2
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do you happen to have a formula for csc (2x)?
@igbasallote no i dont have a formula
Lg lol...ig is another user
@lgbasallote my bad
poor ig haha
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What is the reciprocal of csc(x)? Use that to help solve this problem
^what he said
@lwilson i dont even know what the reciprocal is
csc = 1/sin
you know that csc2x=1/(sin2x), then sin2x=2(sinx)(cosx), so csc2x=1/(2sinxcosx). 1/sinx=cscx, and 1/cosx=secx. to sum up, csc2x=(cscx)(secx)/2
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now find an identity for sin(2x)
\[\large \begin{align} & \csc (2x) = \frac{1}{\sin (2x)}\\\\ & \frac{1}{\sin (2x)} = \frac{1}{2\sin x \cos x}\\\\ & \frac{1}{2\sin x \cos x} = (\frac{1}{2})(\frac{1}{\sin x})(\frac{1}{\cos x}) \end{align} \]
do you get that @kkayla
@lgbasallote yes thanks
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