Solve 3(5)^(2x-3)=6
divide by 3 to both sides then take the natural log of both sides.
divide ln5 to both sides so you now have: 2x-3 = 2/(ln5) can you take it from here?
Possibly =) Is my next step: 4x-6=(ln5)
@dpaInc
no.. just solve for x... add 3 to both sides...
2x= 2/(ln5)+3
yep... now get rid of that 2 on the left by multiplying 1/2 to both sides... :)
what do you get?
x= 1/(ln2.5)+1.5??
why did the 5 change to 2.5? it doesn't...
other than that, your answer is good....
Okay so: x= 1/(ln5)+1.5 Which leads to: x=1/0.698970004 + 1.5
yeah... just use x= 1/(ln5)+1.5 as the exact form. put it in your calculator for an approximation... if you want.
When I round it to the nearest hundredth I get 2.93 =)
lemme check...
hmm. i got 2.121
I probably misentered something =)
no.. i see an error above..
Did I enter a step wrong?
no... i did.. :( sorry but it's easily correctable...
No problem at all! I am glad you caught it =)
actually it occurred in my first post.. "take the natural log of both sides"
so this is what we should've gotten: 2x-3 = ln2/(ln5)
doing the same algebra: 2x = ln2/ln5 + 3 x = (1/2)*(ln2/ln5 + 3)
ok.. let's try that again... punch that into your calculator...
i got x=1.715 and i put this value back into the original equation and it works out.... :)
Thats exactly what I got! =) Except I rounded to the hundredth to get 1.72 =)
good job swim!:)
Thank you!! =) Would you mind helping me with two more?
no..... i don't mind.... :)
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