Question

if sinx= 12/13 find sec

Answer 1

that csc

Answer 2

lol sorry...

Answer 3

Are you aware that:
\[\sin^2\theta+\cos^2\theta=1\]

Answer 4

yes

Answer 5

Perhaps you could utilise this identity in solving your answer :)

Answer 6

well find your third side by doing \[\sqrt{13^2 - 12^2}\]

Answer 7

\(\Large \color{MidnightBlue}{\Rightarrow sinX = {opposite \over hypotenuse} }\)

Clearly, opposite is 12 and 13 is hypotenuse.

\(\Large \color{MidnightBlue}{\Rightarrow secX = {hypotenuse \over adjacent} }\)
Hypotenuse is 13, of course.
Now, we know that 13 is involved in Pythagorean triplet 5,12,13 where 13 is the hypotenuse.
Clearly, 12 is opposite so the only side left is 5(adjacent)
\(\Large \color{MidnightBlue}{\Rightarrow secX = {13 \over 5} = 2{3 \over 5} }\)

Answer 8

Was I right?

Answer 9

@chaise how would i use it

Answer 10

@viictor As far as I am concerned, that has no use. See my post please.

Answer 11

Parth is probably right ^

Answer 12

BTW, you needed csc or sec?

Answer 13

If you needed csc, then:


\(\Large \color{MidnightBlue}{\Rightarrow cscX = {1 \over sinX} }\)

Answer 14

@chaise i believe youre right

Answer 15

Or, you can say that csc is the reciprocal of sin.

Answer 16

i need sec

Answer 17

Then I have given the value of secX.

Answer 18

for all that matters....kohli is right

Answer 19

im not using a triangle!

Answer 20

Trig is all about triangles! :P

Answer 21

where there is sine..there is automatically a triangle young padawan

Answer 22

@viictor BTW why did your second posting say you wanted cosec?

Answer 23

\(\Large \color{MidnightBlue}{\Rightarrow Trigonometry = \text{Measure of triangles.} }\)

Answer 24

@kropot72 I've already mentioned csc.

Answer 25

well goodluck finding someone who can solve it by sin^2 + cos^2 = 1

Answer 26

That's what I say too :0