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Solve for x
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\[\log _{5} (2x-1) = -2\]
Any ideas Vikash? :)
(2x-1) = 5^-2. Now solve for x
U know me Furtive ? today is my first day here although... it it log base 5 ?
yes
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\[(2x-1)=5^{-2}\] jkristia?
yes, then solve for x. The double check by inserting x into the original equation. On your calculator you can check by log(2x-1)/log(5) = ?
How do you remove the power? Sorry :P
you dont, you evaluate it. 5^(-2) = 1 / 5^2 = 1/25
well, yeah - that removes it too :)
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Ahhh, i look silly, thanks man :D
is the answer x = 0.25 = 1/4 ?
is my answer correct ?
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