What is the slope of a line that passes through the point (−2, 3) and is parallel to a line that passes through (3, 7) and (−2, −8)? (4 points)
y = 3x + 9
find the slope between (3,7) and (-2, -7) using (y1-y2)/(x1-x2) = m use that slope and plug it into point-slope form: y-y1=m(x-x1) where x1,y1 are the coordinates of the given point.
still confused
can you calculate the slope between (3,7) and (-2,-8) as i described?
m = slope
i still dont' understand why m stands for slope? was slope named something different before?
mlope?
:)
omg i just dont understand at all
okay... see these two point: (3,7) and (-2,-8) they have an x coordinate (the first number) and a y coordinate (the second number) subtract the second number from each point and divide the difference of the x coordinates.
second numbers (y coordinates) -8, 7. subtract them: -8 - 7 = -15 first numbers (x coordinates): -2, 3. subtract them: -2 - 3 = -5 divide them: -15/-5 = 3 that is your slope.
any help?
yes thank you :)
ok.. with that, you need to put it in poin-slope form: y - y1 = m(x - x1) you already have your slope m = 3. the given point is (-2, 3). just plug those values in to the formula i just stated.
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