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x - 5/4 = 3
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\[\frac{x-5}{4}=3\] multiply both sides by 4\[\frac{4}{1}*\frac{x-5}{4}=\frac{4}{1}*\frac{3}{1}\]
on the left side you can see that the 4's cancel each other and multiplying the right side leaves you\[\frac{x-5}{1}=\frac{12}{1}\] a numerator over 1 is simply the numerator which leads to \[x-5=12\]
so then i have \[4x - 20/ 1 = 12/1 ?\]
oh right
add 5 to both sides so that you don't manipulate the equation \[x-5+5=12+5\] x=17
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so x = 17
check put x=17 into the equation
haha ok thank you very much!
\[\frac{17-5}{4}=3=\frac{12}{4}\]
it's correct
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