I need help simplifying the expression 11^2/5 / 11^4/5 into (the fifth root of 1331) / 11 ...the 5th square root applies only to the 1331 in the numerator! the 11 as the denominator is just an 11! please help!
Is this your equation?\[{\frac{11^2}{5 }\over \frac{11^4}{5}}\div \frac{\sqrt[5]{1331}}{11}\]
where you have the division sign...it should be an equals sign
Like this?\[{\frac{11^2}{5 }\over \frac{11^4}{5}}= \frac{\sqrt[5]{1331}}{11}\]
yes, that is the correct setup
\[{\frac{11^2}{5 }\ \times \frac{5}{11^4}{}}= \frac{\sqrt[5]{1331}}{11}\]Can you simplify it from here?
Im not sure how what is on the left side of the "=" sign can equal what is on the right!
I was wondering that as well. Are you sure that you copied your original equation correctly?\[{\frac{11^2}{5 }\over \frac{11^4}{5}}= \frac{\sqrt[5]{1331}}{11}\]
yea...the answer, on the right of the "=" sign, is what the book says is the answer
The answer to what?
the left side (the problem) is equal to the right side (the answer) ....Im not sure why the answer is the answer!
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