What is the 32nd term of the arithmetic sequence where a1 = -33 and a9 = -121? thanks -396 -385 -374 -363
im not really sure?
well i got 385? but im not sure
ya
Generate a general formula for the \(n\)th term, and then evaluate. Hint: You know it's an arithmetic sequence, so your formula should be linear.\[a_n=\ ?\]
I believe the question is correct. an arithmetic sequence is formed as follows: a, a+d, a+2d, a+3d, ... where 'a' is the first term (which can be written as 1st term)
similarly 32nd term means the thirty-second term in the sequence
i.e. term number 32
a1 is first term a9 is 9'th term
it usually written as:\[a_1,a_2,a_3,...,a_9,...,a_{32},...,a_n\]
the general formula for the n'th term is:\[a_n=a_1+(n-1)d\]where \(a_1\) is the first term and \(d\) is the common difference between each term.
so, using this, we get the 9'th term as:\[a_9=a_1+(9-1)d=a_1+8d\]and you are given:\[a_1=-33\text{ and }a_9=-121\]so use this to solve the question.
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