Question

Find two integers between -10 and 10 that make the equation false

Answer 1

what equation???

Answer 2

it doesn't say thats all it says

Answer 3

oh theres a part a that says
for the following equation, find two integers between -10 and 10 that make the equation true: -2x^2-2x=-4

Answer 4

\[\Large -2x^2-2x=-4\]
\[\implies \Large2x^2+2x-4=0\]\[\implies \Large2\left( x^2+x-2 \right)=0\]

Answer 5

Factor the Left side to get two number for which the equation is true.

any other numbers ... the equation will be false

Answer 6

what about when it says find two integers between -10 and 10 that make the equation false

Answer 7

first you have to find for which is it true.

Answer 8

whic are those?

Answer 9

i don't know hot to find them.

Answer 10

can you factor:
\[ \Large x^2+x-2 \]

Answer 11

Refer to the attached plot.

Answer 12

we had: \[\Large2\left( x^2+x-2 \right)=0\]
divide both sides by 2:\[\implies \Large x^2+x-2 =0\]
\[\implies \Large x^2-x\ +\ 2x-2 =0\]\[\implies \Large x \left( x-1 \right)+2\left( x-1 \right) =0\]
\[\implies \huge (x+2)(x-1) =0\]

Answer 13

so, x+2 = 0 , or x-1 =0

\(\huge x=-2\), or \(\huge x=1\)

plug either of these in the original equation: \(-2x^2-2x=-4\)
and you will get \(\large -4=-4\)

take any other value for x (like x=0, 3, or -1) an the equation will be false