Question

Factor the trinomial: 3x2 + 11x + 6

Answer 1

Is there a factor that is common in each term?

Answer 2

A. (3x + 2)(x + 3)
B. (3x + 3)(x + 2)
C. (3x + 1)(x + 6)
D. (3x + 6)(x + 1)
these are the options

Answer 3

Okay, so basically, we need to find two binomials then when multiplied, they give us the original equation.

Answer 4

So do you know how to foil?

Answer 5

@Haiz, Im trying to teach how to do it, not give the answers!

Answer 6

yes but im not so good at it

Answer 7

Okay, so we need to find two binomials.

So we start by setting up the following:

\(\ \Huge (3x + || )(x + ||) \). We know that the first terms have to equal \(\ 3x^2 \). 3x and x multiplied together equal 3x^2. Next, we know that the outer term has to equal 6. what numbers could we plug in for the space (indicated by the ||) that would equal 6 when multiplied?

Answer 8

the standard equation is ax2+bx+c
here we have 3x2 + 11x + 6
now compare the two equations a = 3, b =11, c =6
now find the product a*c= 3*6=18
now factor 18 such that by addition or subtraction of the factors u get b = 11. which is possible as
18=9*2 (9+2=11)
so we can write the equation as 3x2 + 11x + 6
3x2 + 9x+2x + 6
bracket the terms to make easier (3x2 + 9x)+(2x + 6)
= 3x (x+3)+2(x+3)
=(3x+2)(x+3)

hope u got it..