will someone please teach me how to find the discriminant of the following equation? 9x^2+12x+4=0
for an equation of the form\[ax^2+bx+c=0\]the discriminant is\[b^2-4ac\]
so what would this equation look like, in that form?
Fill in the numbers, he gave you the variables that match up with the equation you gave us. It is all just substitution.
if a=9 then what is b=? and c=?
b=12 and c=4?
correct! now fill in the equation b^2−4ac to find the discriminant
Once you have the numbers substituted in the correct places..it is just simple math solving and simplifying.
When you have the answer I can check it for you.
okay but i still am not to sure. I see where you did that but if i filled out b^2-4ac then would that be 12^2-4?
you forgot to fill in the (a)(c) part after the 4...
so 12^2-4(12)(4)? sorry about this... for some reason i am so lost in this.
close, if a=9 b=12 and c=4 you should have gotten 12^2-4(4)(9).
okay i see that now thank-you for clearing that up! so the answer would be 12^2-4(4)(9)
do the math, simplify and you should get your answer
Did you get an answer?
12^2-144?
almost done solving! you need to simplify more. what is 12^2? then subtract 144 from the answer you get.
so it =0!!
Correct!! Here is a short explanation. What you are having trouble solving is easier than you think ^.^ I hope you understand!
i do now thanks to u!
OH and in my drawing i mixed up the (a) and (c) but when you are solving the equation it usually does not affect your solution.
ok that is fine
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