In a large bag of 100 Skittles®, each of the 5 colors (red, orange, yellow, blue, green) occurs with the same probability. You reach in and select 2 candies. Find the probability that exactly one of the candies is blue.
Given that each of the five colors have equal probabilty so each has probability \[P(red)=P(orange)=P(yellow)=P(blue)=P(green)=\frac 15\] Do you get this part
yeah i under stand the 1/5 but then you pull out two candies which makes it 1/10th right??
Nope, it's not like that, Let's work step by step
ookkk
Do you know combinations?
yeah the blue is 1/5
there are 20 blue skittles
and there are 80 other colored skittles
oso it would be 1/4 chance of pulling out one blue???
Nope we have to pull it out of 100, so \[\frac{20}{100}\] Now the other skittle has to be any other color so there are 80 other skittles and we have one skittle already pulled out, so we have 99 skittles \[\frac{80}{99}\] so the probability is \[\frac{20}{100} \times \frac{80}{99}\]
Do you get this?
so it would be 16%
Nope a little part is left, first tell me did you understand till here?
yeah
You see we pulled a blue first and then pulled other color, we could have first pulled other color and then blue, in that case tell me what would be the probability?
i have no clue
Just read the previous part and try to arrive at the probability
i still get 16%
yeah it'd be the same, add the two
so 18%
uhuh, \[\frac{20}{100}\times\frac{80}{99}+\frac{80}{100}\times\frac{20}{99}\]
thanks
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