Question

he area of the front face of the analog clock shown below is 50.24 square inches. The length of the minute hand is 0.25 inches less than the radius of the front face.
http://go.flvs.net/courses/1/flvs_57_3641_12676/ppg/respondus/pool_Geom_3641_0810_12/image0014e68c4f6.jpg
What is the length of the arc the minute hand makes when it moves from the number 3 to the number 7 on the clock?
Answer

1.31 inches

7.85 inches

8.37 inches

23.55 inches

Answer 1

Front face radius is 4" from
\[Area_{circle} = pi * r^2\]
That means the minute hand radius is 3.75"
From three to seven the hand moves 1/3 of a complete revolution so the length of arc should be 1/3 the circumference.
\[ArcLength=1/3 * Circumference\]
\[ArcLength=1/3 * 2*pi*radius\]
giving you 8.375"

Answer 2

ur amazing! lo thanks =)

Answer 3

lol*