Question

Help Algebra is not my best I need to solve this
L =P-2W
__________
2 ?

Answer 1

Solve for what?

Answer 2

Part A: Solve for P. After solving this formula for P, explain the use of the formula.
Part B: Next, create your own values for W and L. Compute your value for P with your own data.

Answer 3

\[\Large L = \frac{P - 2W}{2}\]


\[\Large 2L = P - 2W\]


\[\Large 2L + 2W = P\]


\[\Large P = 2L + 2W\]


For part B, plug in any two numbers you want for L and W. Then evaluate the right side to find P.

Answer 4

wow that took you a couple of seconds I have been trying how about a rate and distance problem?

Answer 5

sure go ahead and ask

Answer 6

The number of miles remaining for a jet traveling from San Francisco to New York can be approximated with the linear equation Miles remaining = 2650 - 475t where t is the number of hours since leaving San Francisco.

Part A: In how many hours will the jet be 1,000 miles from New York?
Part B: How long will the whole trip take?

Answer 7

m = miles remaining

m = 2650 - 475t


1000 = 2650 - 475t


1000-2650 = -475t


-1650 = -475t


-1650/(-475) = t


3.47368 = t


t = 3.47368


So it will be roughly 3.47368 hours when the jet is 1000 miles from new york


For part b), plug in m = 0 and solve for t.

Answer 8

A runner's heart rate in beats per minute is given by the formula Heart rate = 65 + 53 / (4t + 1) where t is the number of minutes after the start of a cool-down period.

Part A: Find the runner's heart rate in 10 minutes.
Part B: When is the runner's heart rate equal to 68 beats per minute?

Does this use the same formula as rate and distance?

Answer 9

No, this is an entirely different problem. But you follow the same basic steps to solve the equation.

part A) plug in t = 10 and evaluate/simplify

part B) set the entire right side equal to 68 and solve for t

Answer 10

Gosh thank you I have been struggling as I said its not my best but you really made my day, in just a few minutes I am impressed...

Answer 11

I'm glad I could help you out

Answer 12

Part B: Next, create your own values for W and L. Compute your value for P with your own data.

This part?

Answer 13

yep

Answer 14

Alright, which values did you pick for L and W?

Answer 15

5 and 10

Answer 16

Alright, so plug them into the equation

P = 2L + 2W

what do you get?

Answer 17

15?

Answer 18

P = 2L + 2W

P = 2(10) + 2(5) ....simply replace L with 10 and W with 5

Answer 19

then what?

Answer 20

subtract 2 from each

Answer 21

2(10) means 2 times 10

Answer 22

so we multiply each 10 and 5 by 2

Answer 23

then since it is + subtract?

Answer 24

no, simply add since you're not isolating any terms

Answer 25

so p=30

Answer 26

good

Answer 27

do you have a tutoring sight?

Answer 28

or you can email me if you like (it's on the site)

Alternatively, you can use msn or yahoo messenger to get in contact with me (my screen name is the same as my name here)

Answer 29

Did you have any other questions?

Answer 30

I will be back I am on the West Coast you? I am registered at algebra.com as of a few minutes ago I am failing algebra and its part of my associates, Just need to understand Algebra, Its hard to teach a OLD dog new tricks..LOL

Answer 31

lol glad you signed up there as I tutor over there as well (small world lol), feel free to email me or add me on msn or yahoo messenger

oh and yes, I'm in CA, so I'm also on the west coast

Answer 32

Great thanks

Answer 33

you're welcome

Answer 34

Hey Jim_thompson5910 are you still on here

Answer 35

. A cell phone company has offered you two different rates. The first rate is $35 per month and 5 cents per phone call (time does not matter). The second offer is $55 per month and 2 cents per call.

Part A: Set up and solve the inequality to model this problem and find where it is less expensive to go with the second plan.

The cell phone company also has two texting plans. The first is unlimited texts for $12. The second plan is 8 cents per text.

Part B: Set up and solve an inequality to show when it less expensive to go with the second texting plan.