Question

if p and q are the roots of X^2 + 2px +q-6=0 the value of p equals?

Answer 1

use the property of sum of roots and product of roots...it is in class 10 syllabus

Answer 2

yes i used but not getting

Answer 3

sum=-b/a product= c/a

Answer 4

ok..what is a,band c here??

Answer 5

it is ax^2 + bx +c

Answer 6

so put the values in equation..where are u finding problem??

Answer 7

p+q=-2p pq=q-6

Answer 8

is that correct

Answer 9

i am stuck at next step

Answer 10

yes looks so..is q=-19/3

Answer 11

from pq=q-6 q=q-6/p...

Answer 12

we have to find the value of p..

Answer 13

oh it was q=-9 so p=5/3 i think..

Answer 14

the answer is -1 , 2

Answer 15

\[x ^{2}+(\alpha + \beta)x + \alpha \beta\]...

Answer 16

@satellite73 plzz help

Answer 17

plzz antone solve for it....

Answer 18

so than p+q=-2p and p*q=q-6

p+q=-2p
p*q=q-6

- so just you need to solve this system for q and p

Answer 19

\[p+q=-2p\]
\[pq=q-6\]

Answer 20

first one gives \(q=-3p\)

Answer 21

ok

Answer 22

then too the eq is in p and q

Answer 23

-3p^2=q-6

Answer 24

who will put q=-3p in r.h.s

Answer 25

substitute in to second one get
\[-3p^2=-3p-6\]
\[3p^2-3p-6=0\]
\[3(p^2-p-2)=0\]
\[(p-2)(p+1)=0\]
\[p=2, p=-1\]

Answer 26

probably easier to solve using quadratic formula or easier still to complete the square

Answer 27

I think u should get it now @shameer1

Answer 28

ok

Answer 29

ignore 9π
http://screencast.com/t/MdMY5b0u