Given the points S(-4,3) and T(-2,5), write an equation for which ST is the diameter.
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OpenStudy (anonymous):
I got:
(x+3)^2 + (y-4)^2 = 1
OpenStudy (anonymous):
am I correct?
OpenStudy (binary3i):
but not equal to 1
OpenStudy (binary3i):
\[=2\sqrt{2}\]
OpenStudy (anonymous):
:/
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OpenStudy (anonymous):
How'd you get that?
OpenStudy (binary3i):
sorry not that but equal to 8
OpenStudy (binary3i):
because that is the radius
OpenStudy (anonymous):
The general form of a circle with center \((h,k)\) is
\((x-h)^2+(y-k)^2=r^2\)
OpenStudy (anonymous):
@binary3i I got √2 as the radius
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OpenStudy (binary3i):
oh yeah you are correct.
OpenStudy (anonymous):
from what I got my answer is :
(x+3)² + (y-4)² = 2
OpenStudy (anonymous):
(-4,3) isn't the center. Its a end point of the diameter.
OpenStudy (binary3i):
correct
OpenStudy (anonymous):
You are right! I need to read more carefully.
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OpenStudy (anonymous):
so I went and found the midpoint and got (-3,4)
and found the distance between the midpoint and one of the points given and got the square root of 2
I just want to know if my answer is right or if I made a mistake:
(x+3)² + (y-4)² = 2