Solve the system of equations algebraically. (Fractions) M/4 - N/4 =1 M/6 - N/4 =1
subtract the bottom equation from the top to solve for M. plug M into the second equation to solve for N.
another way to do it, which I'm still a little iffy about it, but by all means its there @nsutton would this work? tweak with the equation, the first one lets say: m/4-n/4=1 = m/4=1+n/4 = m=4+n and then in the next equation plug in for m (4+n)/6 - n/4 = 1 and then just solve for n which later will give you m
M/4 - N/4 =1, M/6 - N/4 =1 (M-N)=4, 2M-3N=2 M=4+N, 2(4+N)-3N=2 SOLVE THE TWO EQUATIONS
@rits27 on your second line second equation did you mean 12 also on the third line.. seems to me you multiplied everything by 12
also, since m/4-n/4=1 and m/6-n/4=1 you can say that they are both equal to each other and thus: m/4-n/4=m/6-n/4 and then you can combine like terms and still get what I sated above
Yes you take a factors of 6 and 4 and then multiply both sides by it
so for the first equation you divide by 4?
first equation you multiply by 4 both sides
to solve for M? (M/4 - 4/N = 1) becomes M-N =4
what was done there was that it was tweaked, whatever you do to the right, you do the the left. in this case you want to isolate the M so you add N to both sides
Yes
so it becomes M = N+4?
Now substitute the value of M i.e. N+4 in the other equation
Does the second equation need to be multiplied also?
@seattle12345 not if you have multiplied one already. multiplying in this case allows you to work without fractions. So I guess it depends. If you want to work with fractions or not. Which working without them does make it simpler usually..
yea I would choose not to work with fractions. so in the second equation we end up with 2M -3N = 2... How did we end up with the 2(constant) if we multiplied by 12? sorry if its a stupid question.
12M/6 is 2M
and 12*N/4 is 3N
sorry I mean the (=2)
Its not 2 its 12 actually
oh ok, it makes more sense now lol
so N=4?
N= -4?
2(4+N)-3N=12 ie 8+2N-3N=12 ie -N=12-8 ie N=-4.
Thanks for your help @rits27 @nsutton and @juan_9292! you guys are amazing!
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