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Mathematics 20 Online
OpenStudy (seattle12345):

Solve the system of equations algebraically. (Fractions) M/4 - N/4 =1 M/6 - N/4 =1

OpenStudy (anonymous):

subtract the bottom equation from the top to solve for M. plug M into the second equation to solve for N.

OpenStudy (anonymous):

another way to do it, which I'm still a little iffy about it, but by all means its there @nsutton would this work? tweak with the equation, the first one lets say: m/4-n/4=1 = m/4=1+n/4 = m=4+n and then in the next equation plug in for m (4+n)/6 - n/4 = 1 and then just solve for n which later will give you m

OpenStudy (anonymous):

M/4 - N/4 =1, M/6 - N/4 =1 (M-N)=4, 2M-3N=2 M=4+N, 2(4+N)-3N=2 SOLVE THE TWO EQUATIONS

OpenStudy (anonymous):

@rits27 on your second line second equation did you mean 12 also on the third line.. seems to me you multiplied everything by 12

OpenStudy (anonymous):

also, since m/4-n/4=1 and m/6-n/4=1 you can say that they are both equal to each other and thus: m/4-n/4=m/6-n/4 and then you can combine like terms and still get what I sated above

OpenStudy (anonymous):

Yes you take a factors of 6 and 4 and then multiply both sides by it

OpenStudy (seattle12345):

so for the first equation you divide by 4?

OpenStudy (anonymous):

first equation you multiply by 4 both sides

OpenStudy (seattle12345):

to solve for M? (M/4 - 4/N = 1) becomes M-N =4

OpenStudy (anonymous):

what was done there was that it was tweaked, whatever you do to the right, you do the the left. in this case you want to isolate the M so you add N to both sides

OpenStudy (anonymous):

Yes

OpenStudy (seattle12345):

so it becomes M = N+4?

OpenStudy (anonymous):

Now substitute the value of M i.e. N+4 in the other equation

OpenStudy (seattle12345):

Does the second equation need to be multiplied also?

OpenStudy (anonymous):

@seattle12345 not if you have multiplied one already. multiplying in this case allows you to work without fractions. So I guess it depends. If you want to work with fractions or not. Which working without them does make it simpler usually..

OpenStudy (seattle12345):

yea I would choose not to work with fractions. so in the second equation we end up with 2M -3N = 2... How did we end up with the 2(constant) if we multiplied by 12? sorry if its a stupid question.

OpenStudy (anonymous):

12M/6 is 2M

OpenStudy (anonymous):

and 12*N/4 is 3N

OpenStudy (seattle12345):

sorry I mean the (=2)

OpenStudy (anonymous):

Its not 2 its 12 actually

OpenStudy (seattle12345):

oh ok, it makes more sense now lol

OpenStudy (seattle12345):

so N=4?

OpenStudy (seattle12345):

N= -4?

OpenStudy (anonymous):

2(4+N)-3N=12 ie 8+2N-3N=12 ie -N=12-8 ie N=-4.

OpenStudy (seattle12345):

Thanks for your help @rits27 @nsutton and @juan_9292! you guys are amazing!

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