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5^(x+1) = 6^(2x) solve for x and I'm pretty sure you have to use log or ln.
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yes
if you can please help me work this out?
take the natural log of both sides of the equation to remove the variable from the exponent ln(5^(x+1))=ln(6^(2x)) xln(5)+ln(5)=ln(6^(2x)) Simplify the result xln(5)+ln(5)=ln((36)^(x)) xln(5)+ln(5)-xln(36)=0 Factoring x(ln(5)-ln(36))=-ln(5) solve for x from here
Alright thank you so much @.Sam.
welcome
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