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solve x^3 is less than 25x
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x^3 < 25 x x^3 - 25 x < 0 x (x^2 - 25) < 0 for x > = 5, x^2 - 25 > = 0 and x too will be > = 0, so x (x^2 - 25) > = 0 for x = < -5, x^2 - 25 > = 0 and x < = 0, so x (x^2 - 25) < = 0. Your answer: x < - 5.
Not one of my possible answers.
Really? What's the answer in the book?
1)-5<x<0 or x>5 ,/ 2) -5<x<5 /3) x<-5 orx>5 /4) x<-5or 0<x<5
Or x >0 and x <5.
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4) x<-5or 0<x<5
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You're welcome. :)
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