A rescue helicopter flew from its home base for 35 km on a course of 330 degrees to pick up an accident victim. It then flew 25 km on a course of 090 degrees to the hospital. What distance and on what course will the helicopter fly to directly return to its home base?
330 degrees is the same as 30 degrees to the southeast. 35cos(30 degrees) km east = 30.3108891324553 km east 35sin(30 degrees) km south = 17.5 km south Next he flew 25 km due north So overall, he flew 30.3108891324553 km east, and (25 - 17.5) = 7.5 km north So he must fly southwest to get back. Fly south 7.5 km, and Fly west 30.3108891324553 km Magnitude of distance is sqrt(7.5^2 + 30.3108891324553 ^2) = 31.225 km (looks good so far) Direction = 180 + arctan(7.5/30.3108891324553 ) = 194 degrees
I'm looking at a unit circle and are you saying that 330 degrees southeast = 30 degrees northeast?
how would it look like? like this: |dw:1337881549579:dw|
can someone please draw it out? I don't understand..
Since this is a question involving navigation, you must use compass degrees...which is different than what a cartesian plane would show. Here's a picture which should help...you just need to solve the triangle to find the length of the of last line (and angle) for the plane to get back to home base.
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