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Mathematics 15 Online
OpenStudy (anonymous):

picture attached: A holiday resort has two rectangular-shaped pools, including a swimming pool for adults and a wading pool for children. The two pools are similar in shape and have dimensions, in meters, as shown in the figure below. What is the value, in meters, of x?

OpenStudy (anonymous):

picture

OpenStudy (anonymous):

you can use pretty much any ratio you like

OpenStudy (anonymous):

here are the choices What is the value, in meters, of x? Answer 4 2 5 1

OpenStudy (anonymous):

for example \[\frac{20}{2x}=\frac{30}{2x+2}\] which is somewhat annoying because the variables are in the denominator so you can also use \[\frac{2x}{10}=\frac{2x+2}{30}\] or even \[\frac{20}{30}=\frac{2x}{2x+2}\]

OpenStudy (anonymous):

pick one and we can solve it

OpenStudy (anonymous):

4

OpenStudy (anonymous):

i meant pick a ratio, one of the ones i wrote above we can solve any of them, they are all the same

OpenStudy (anonymous):

last 1

OpenStudy (anonymous):

ok start with \[\frac{20}{30}=\frac{2x}{2x+2}\] now probably best thing to do is reduce to get \[\frac{2}{3}=\frac{2x}{2x+2}\] then we can cross multiply to get the variable out of the denomiator and write \[2(2x+2)=3\times 2x\] and i bet you can solve it form here

OpenStudy (anonymous):

so 4x + 4 = 3 * 2x ?

OpenStudy (anonymous):

yes maybe write \(4x+4=6x\)

OpenStudy (anonymous):

then 8x = 6x?

OpenStudy (anonymous):

careful here \(4x\) and 4 are not like terms. you cannot add them subtract \(4x\) from both sides

OpenStudy (anonymous):

so 4 = 2x?

OpenStudy (anonymous):

\[4x+4=6x\] \[4=6x-4x\] \[4=2x\]

OpenStudy (anonymous):

right. now divide by 2 and you are done

OpenStudy (anonymous):

sorry OS crashed again for me... so 2 = x?

OpenStudy (anonymous):

yes you got it so one side is \(2\times 2=4\) and the other is \(2\times 2+2=6\)

OpenStudy (anonymous):

but your question said solve for \(x\) so your answer is 2

OpenStudy (anonymous):

gotta run, good work

OpenStudy (anonymous):

alright got it. Thanks Satellite73 :)

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