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Mathematics 18 Online
OpenStudy (anonymous):

Prove the formulas \(\Large{\max(a,b)=\frac{a+b+|a-b|}{2}}\), \(\Large{\min(a,b)=\frac{a+b-|a-b|}{2}}\) for \( a,b \in\mathbb{R}\). Show as a corollary: For continuous functions \(f,g:X\rightarrow \mathbb{R}\) on a metric space \(X\) the function \(\max(f,g):X\rightarrow \mathbb{R}\) defined by \(\max(f,g)(x)=\max(f(g),g(x)\), is continuous as well. Analogously for \(\min(f,g)\).

OpenStudy (anonymous):

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