The Digit in the unit place of the product 127^79 * 2^24?
@UnkleRhaukus
plzz help
can i use a calculator?
no
any tricks???
calculator didn't help at all
i think there is some tricks to do it....
can you make 127 simpler?
i can not see the trick to this yet
@heena plzz help
well it turns out that 127 is a prime number
i dont know if this helps or not
@heena can u solve this......
wait lemme see i didnt read qn yet lol :P
ok
it so long :O @Ishaan94 u have scientific calculator plz do dis..
i think there is a trick for doing this
the product has over 170 places, a calculator will not help here
7^1 = 7 7^2 = 49 7^3 = ...3 7^4 = ...1 7^5 = ...7 2^1 = 2 2^2 = 4 2^3 = 8 2^4 = 16 2^5 = 32 127^79 = ...1? 2^24= ...6? So, 6?
The answer is 8 plzz check it
Ohh hmm I must have done silly mistake
Yes, 127^79= ...3 6x3 = 18 and 8 is the answer
can u tell the tricks used..
i do not understand how you did that @Ishaan94
Hmm 23*24 = ...2, we only need to get multiplication of the digits in unit place. so, to get unit place digit for 127^(79)*2^(24), we need get unit place of 7^(79)*2^24
yeah i get that bit , but i don not get how you found the unit place of 7^{79}=....3
how u get the unit digit for 2^24 as 6 and other as 3//
@satellite73
their unit digits repeat after certain number of multiplication. 7^1 = 7 7^2 = 49 7^3 = 343 7^4 = 2401 7^5 = 16807 7^6 = 117649 7^7 = 823453 7^8 = 5 764 801 try to see the pattern you will realize. i am not a good teacher, sorry.
so.....
i think i see what you are getting at @Ishaan94
after 4 powers, 7 gets back to 1st form. 79 = 80 -1 => 79=4*20 - 1. so, 7^79 must be of ...3 form
i didn't know there were such patterns for powers
then for 2^24
Try it yourself. :-) 4,8,16,32,...
so it repeates after 6 so 2^24 must be 6 is that the way
No not 6 but 4 2,4,8,16,32,64,128,256,512,...
hey it repeates after 16
it does, but the actual interval is 4 not 16.
ok
1,3,9,27,81,243,279,2197,..1,..3,..9,..7,..1,..3,...9,...7,......
kinda reminds me of repeating decimals
I got it))) http://www.wolframalpha.com/input/?i=127%5E79+*++2%5E24 The last digit in the resultant number is 8.
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