Question

The graph of which quadratic equation is shown below?

Answer 1

y = x^2 + 6x - 5
y = x^2 - 6x - 5
y = -x^2 - 6x - 5
y = -x^2 + 6x - 5

Answer 2

vertex at (3,4)
Point at x=1 x=5
(x-1)(x-5)=0
expand and get your equation

Answer 3

from the graph, you can know that the roots of the equation are 1 and 5.
So, (x-1)(x-5) =0
Expand it ...
.... Well.. I'm slow :|

Answer 4

For quadratic,
(x-α)(x-β) =0, where α and β are the roots of the equation.

Answer 5

so whats the answer?

Answer 6

how do i expand?

Answer 7

I guess you have to use SOR and POR
SOR=1+5=6
POR=5
---------------------------------
x^2-( SOR )x+( POR )=0
x^2-6x+5=0
you have to reverse the whole equation because the graph pointing downwards
-x^2+6x-5=0

Answer 8

Or use ''traditional'' method to expand it.
(x-1)(x-5)=0
x(x-5) - 1(x-5) =0
x^2 -5x -x +5 =0
x^2 - 6x +5 =0