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What is the sum of the arithmetic sequence 6, 14, 22 …, if there are 26 terms?
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a=6 ,d=8 ,n=26 apply the rule Sn=n/2(2a+(n-1)d) _____ Where a= first term ,d=difference between eveery two terms ,n = number of all terms
s26= 26/2 (2(6)+(26-1)8
so the answer is 2756?
right ":D
What is the 25th term of the arithmetic sequence 9, 15, 21, … ? so with this one it would be s25=25/2 (2(9) + (25-1)6
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so the 25th term would be 153?
yea,u calculate it XD
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