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Solve this system of equations. Hint: Use graphing, substitution, or elimination to find the points (x,y) that make both equations true.(pic attached)
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the circle has a centre at the origin and radius of 8 the ellipse has a centre at the origin and major axis length of 8 minor axis length of 1 the points of intersection are (-8, 0) and (8, 0) |dw:1337986488389:dw|
algebraically since both equations are equal to 64 equate them \[x^2 + y^2 = x^2 + 64y^2 = 63y^2 = 0\] then y = 0 substitute into the circle x^2 + 0 = 64 \[x = \pm 8\]
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