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Mathematics
need help! The Equation of the sides of a quadrilateral ABCD are as follows AB: 4y+x=20 BC: x=0 CD:y+2x=2 AD: 3y=4x-4 Find the coordinates of A, B, C and D a=by a graphical method
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solve all of them, then see such points which are only on two lines not more than that.
Solve AB: 4y+x=20 BC: x=0 To get B Solve BC: x=0 CD:y+2x=2 To get C Solve CD:y+2x=2 AD: 3y=4x-4 To get D Solve AB: 4y+x=20 AD: 3y=4x-4 To get A
thank you!
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