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Mathematics
OpenStudy (anonymous):

Attachment.

OpenStudy (anonymous):

OpenStudy (asnaseer):

lets call the amount of water in the container with less water x, and the amount of water in the other one y. then we can say: x + y = 35

OpenStudy (asnaseer):

so if we pour 7 quarts from container with x into container with y, how much water will be left in the container that had x to start with?

OpenStudy (anonymous):

x-7=y+7?

OpenStudy (asnaseer):

x-7 is how much is left in the original container x+7 is how much will now be in the other container they are not equal however

OpenStudy (anonymous):

true.....okay i kinda get it...

OpenStudy (asnaseer):

it says the container with more water now contains 4 times as much as the other one, so we can say: y + 7 = 4(x - 7)

OpenStudy (asnaseer):

so you now have two equations in two unknowns

OpenStudy (asnaseer):

x + y = 35 y + 7 = 4(x - 7) you should be able to solve these to find x and y.

OpenStudy (anonymous):

yeah but x can = 35-y

OpenStudy (anonymous):

so.....i'll plug it in

OpenStudy (asnaseer):

yes - you can solve using that method

OpenStudy (anonymous):

okay.....so i got y= 19.6 and x = 15.4 correct?

OpenStudy (asnaseer):

that does not match my answers. maybe if you describe your steps here then I can help you spot where you (or I) made a mistake?

OpenStudy (anonymous):

my math is wrong....just a min. please

OpenStudy (anonymous):

x=14 y=21?

OpenStudy (asnaseer):

yes - that matches my answers

OpenStudy (anonymous):

thanks!

OpenStudy (asnaseer):

yw

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