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Mathematics

OpenStudy (anonymous):
Attachment.

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OpenStudy (anonymous):
OpenStudy (asnaseer):
lets call the amount of water in the container with less water x, and the amount of water in the other one y.
then we can say:
x + y = 35

OpenStudy (asnaseer):
so if we pour 7 quarts from container with x into container with y, how much water will be left in the container that had x to start with?

OpenStudy (anonymous):
x-7=y+7?

OpenStudy (asnaseer):
x-7 is how much is left in the original container
x+7 is how much will now be in the other container
they are not equal however

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OpenStudy (anonymous):
true.....okay i kinda get it...

OpenStudy (asnaseer):
it says the container with more water now contains 4 times as much as the other one, so we can say:
y + 7 = 4(x - 7)

OpenStudy (asnaseer):
so you now have two equations in two unknowns

OpenStudy (asnaseer):
x + y = 35
y + 7 = 4(x - 7)
you should be able to solve these to find x and y.

OpenStudy (anonymous):
yeah but x can = 35-y

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OpenStudy (anonymous):
so.....i'll plug it in

OpenStudy (asnaseer):
yes - you can solve using that method

OpenStudy (anonymous):
okay.....so i got y= 19.6 and x = 15.4 correct?

OpenStudy (asnaseer):
that does not match my answers. maybe if you describe your steps here then I can help you spot where you (or I) made a mistake?

OpenStudy (anonymous):
my math is wrong....just a min. please

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OpenStudy (anonymous):
x=14 y=21?

OpenStudy (asnaseer):
yes - that matches my answers

OpenStudy (anonymous):
thanks!

OpenStudy (asnaseer):
yw

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