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If cos x cos (pi/7) + sin x sin (pi/7) =-√2/2, then x can equal: more than one answer: a. 3pi/4+pi/7+2 n pi b. 7 pi/4 + pi/7 +2 n pi c. pi/4 + pi/7 +2n pi d. 5pi/4 + pi/7 +2 n pi
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\[\cos a \cos b- \sin a \sin b=\cos (a+b)\] use this. now solve.
can you help more please
\[\cos x \cos \pi/7 + sinx \sin \pi/7= \cos(x-\pi/7)= -\sqrt{2}/2=-1/\sqrt{2}\] \[\cos \theta=-1/\sqrt{2}.. then \theta = 3\pi/4 + 2n \pi =(x-\pi/7)\] now try to solve it.
answer is a.
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