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Find the common ratio of the geometric sequence whose first term is 3 and sixth is 96.
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ummmm...... i don't really understand the question :P what do you mean, the common ratio??? like, the nth term?? we can't do THAT unless we have all the terms.
first term=a=3 6th term=T6=ar^5 subistitute a in the 2nd equation and solve
3r^5=96 r^5=96/3
5th root to both sides and u get the ratio ;
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so r = 2
what does ar means?
a=First term . r=common ratio . where the nth term in G.s = ar^(n-1)
Ohhhhhh..Thanks! :D
Yrw
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