Question

What is the 8th term of the geometric sequence where a1 = 1024 and a3 = 64,

Answer 1

powers of two

Answer 2

a3 = third term = a1r^2
now you can find r

and eighth term = a1 r^7

Answer 3

The 2nd one would be 2^8 because a1 is 2^6 and a3 is 2^10....So, it'd be 2^(4 + 2n)
2^(4 + 16)
2^20

Answer 4

Calculator to calculate 2^20 :P

Answer 5

what does 1048576 have to do with anything?

Answer 6

Yep

Answer 7

I am confused:(

Answer 8

It's a geometric sequence, and we're multiplying 4 everytime.

Answer 9

thats wrong its not in my answers, its not even close