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Mathematics 18 Online
OpenStudy (anonymous):

Can someone explain to me how I'm supposed to read this?

OpenStudy (anonymous):

Parth (parthkohli):

this is easy, where's the problem? These are functions.

OpenStudy (anonymous):

well can you walk me through the first one so i know how to do the rest?

Parth (parthkohli):

Well okay. Can you tell me what f of 3 is from the table?

OpenStudy (anonymous):

2?

Parth (parthkohli):

No, see the x table, now see what is f(x) in that row.

Parth (parthkohli):

f(1) = 4 f(2) = 3 like that.

OpenStudy (anonymous):

so its 5

Parth (parthkohli):

Yep :)

OpenStudy (anonymous):

and then?

Parth (parthkohli):

So that'd then become g(5). What is g(5) in that table?

OpenStudy (anonymous):

4

Parth (parthkohli):

So we can say: \(g(f(3)) = 4\) :D

OpenStudy (anonymous):

oh ok well what happens when we get into the negatives?

Parth (parthkohli):

That actually is the inverse function of x.

OpenStudy (anonymous):

ok so can we fo f. together?

Parth (parthkohli):

In the inverse function of f(x), you do the opposite.

OpenStudy (anonymous):

*do

Parth (parthkohli):

You see the f(x) table and then see the values in x table.

Parth (parthkohli):

For example, \(\Large \color{Black}{\Rightarrow f^{-1}(4) = 1 }\)

OpenStudy (anonymous):

so the answer for f is 2?

Parth (parthkohli):

f-1(5) = 3

Parth (parthkohli):

g-1(4) = 5

OpenStudy (anonymous):

i was talking about letter f but ya i think i got it

OpenStudy (anonymous):

and is c 1?

Parth (parthkohli):

Yes.

Parth (parthkohli):

You go from the range to domain in inverse functions.

Parth (parthkohli):

f(f(3) = f(5) = 1

Parth (parthkohli):

I think you're getting the idea now.

OpenStudy (anonymous):

ok i get it. and on e do i just substitute a;; the x's for 2?

OpenStudy (anonymous):

*all

Parth (parthkohli):

See the g(x) table, where do you find 4? If you do then what is the value of x?

OpenStudy (anonymous):

wait on what letter?

Parth (parthkohli):

In the g(x) table, we see 4 sittin right there, and the x value for g(4) is 5. so g-1(4) = 5

Parth (parthkohli):

Let me explain. x is the domain(the input) and range is f(x) or the range or the output.

OpenStudy (anonymous):

ya, are you talking about the last question? the h(x) one?

Parth (parthkohli):

If it is g(2) for g(x), then all x's will become 2.

OpenStudy (anonymous):

so it would read -3f(3)-2g(2)+6-6

Parth (parthkohli):

Yes :)

Parth (parthkohli):

Then isolate g(2)

OpenStudy (anonymous):

final answer is -25?

Parth (parthkohli):

Check it.

Parth (parthkohli):

From the table I mean

OpenStudy (anonymous):

so its wrong?

Parth (parthkohli):

I'm too lazy to solve lolol

OpenStudy (anonymous):

ok ill just go w/ -25

Parth (parthkohli):

Okay

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