Question

A World-Language professor adds 13.6 mL of 0.17M HCl to 100.0 mL of 0.448M NaOH. What will the pH of the solution be?

Answer 1

tip1. write down reaction taking place
tip2. work out initial amounts of reactants
tip3. work out amounts after reaction

Answer 2

i dont know what reaction is taking place, help!

Answer 3

Then why are you trying to solve such problems? It's just a waste of time for you if you do not know the basics.

Read your textbook on acid-base reactions first.

There is no acid-base reaction simpler than the one taking place in your problem.

Answer 4

HCl + NaOH -> H2O + NaCl

Answer 5

i dont see the H30 or OH though, how do i find pH?

Answer 6

ok!

Now you can simplify your equation as HCL does not exist in solution but forms H3O+ and Cl-, whereas NaOH dissolves completely.

Answer 7

h3o + cl + NaOH -> h2o + NaCl???

Answer 8

NaOH does not exist either. It will be in ionic form.
That should be in your textbook too.

Answer 9

so its just h3o + oH + Na + Cl -> h2o + NaCl?

then from here, how do i apply the values given in the question?

Answer 10

Leave out the Na+ ,Cl- and NaCl.

then go to tip2.

Answer 11

so the concentration of h3o would be 13.6 * .17= 2.312 (didnt convert to L) and concentration of OH would be 100* .448 = 44.8?

Answer 12

These are not concentrations but amounts in millimoles.
Apart from that, that's correct.

Answer 13

what do i do from there? will the equation be 1.0x10^-14 = x/((2.312-x)(44.8-x))?

Answer 14

wait nevermind, water can't be in an equilibriume equation...so how do i set up my equilibrium expression?

Answer 15

You have to work out amounts after reaction.

There is no 'magic' equation. You have to understand what happens to the substances that you have put together.

Answer 16

you should learn to answer questions like this guy:

http://answers.yahoo.com/question/index?qid=20080504193856AADPB6x

Answer 17

There must be some misunderstanding here!

People here are not supposed to 'answer' your questions, but lead you and help you correct your own mistakes. Method to solve these basic problems are found in all textbooks and on the web, so use them.

Answer 18

@scrubbyduck If you want Yahoo Answers quality help, then perhaps you should use Yahoo Answers? We seek to provide quality tutoring here. That involves you working on the problem on your own with guidance.

@Vincent-Lyon.Fr Please do note that your tone is coming off somewhat condescending. While I'm sure you wrote those words with a light hearted jest in mind, I don't feel that jest was accurately communicated here - making you come off as a little bit mean.