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OpenStudy (anonymous):
OpenStudy (anonymous):
First, make the denominators equal.
OpenStudy (anonymous):
That's the part I don't know how to do.
OpenStudy (anonymous):
You need to find a number which is a factor of both 10 and 6
OpenStudy (anonymous):
No wait sorry I meant multiple. A multiple of both 10 and 6.
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OpenStudy (anonymous):
2
OpenStudy (anonymous):
No, that's the factor. Sorry my bad, I meant multiple. So we need a number that is divisible by both 10 and 6.
OpenStudy (anonymous):
60?
OpenStudy (anonymous):
30
OpenStudy (anonymous):
sry
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OpenStudy (anonymous):
Yes, 30. 60 works too but it's easier with 30. So now the denominator has to be 30. This means you need to multiply them by a number so they each become 30. But if you're multiplying the denominator, you need to multiply the numerator with the same number so the fraction doesn't change.
OpenStudy (anonymous):
so three and five.
OpenStudy (anonymous):
and when i multiply the deno and numer by # do i use the distributive property,
OpenStudy (anonymous):
Yes.
OpenStudy (anonymous):
so the answer is (2y-6)/30
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