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OpenStudy (cwrw238):
use complementary angle method
OpenStudy (anonymous):
I kind of forgat how to use it
OpenStudy (cwrw238):
i'm stretching my memory as well....
OpenStudy (cwrw238):
i think you can use
Rcos (x + a) = Rcosxcosa - Rsinxsina
now compare this with
3cosx - 4sinx = 0
and compare coefficients
hmm... maybe there an easier way though..
maybe you can use sinx = square root(1 - cos^2 x)
OpenStudy (cwrw238):
4 square root(1 - cos^2x) = 3 cos x
16(1 - cos^2 x) = 9cos^2 x
solve for x
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OpenStudy (cwrw238):
that gives cos^2x = 16/25
cos x = 4/5 or -4/5 right?
OpenStudy (anonymous):
Yeah right my textbook says the same answer,but one question how did you get the 16
OpenStudy (cwrw238):
i squared ;4 square root(1 - cos^2x)'
OpenStudy (cwrw238):
squaring both sides
OpenStudy (anonymous):
Oh okay now it makes sense to me thanks for your help
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OpenStudy (cwrw238):
yw
OpenStudy (cwrw238):
thats ne finished tonight - i must drink some cwrw