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Mathematics 21 Online
OpenStudy (anonymous):

Find A and B: x+5 = A(x+2) + B

OpenStudy (anonymous):

You need more information to solve this (i.e., two more equations relating \(x\), \(A\), and \(B\)).

OpenStudy (anonymous):

This is from a partial fraction problem: (x+5)/(x+2)^2

OpenStudy (anonymous):

Ah I see... you're restricting \(A\) and \(B\) to be constants. Look at this rearrangement:\[x+5=Ax+(2A+B)\]We have \(1x\) on the left and \(Ax\) on the right, so what must \(A\) be? Now, what must \(B\) be?

OpenStudy (anonymous):

Cheers! A =1, therefor B = 3

OpenStudy (anonymous):

Good work!

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