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Mathematics 23 Online
OpenStudy (anonymous):

Please help Simplify:

OpenStudy (anonymous):

Parth (parthkohli):

Try to factor the numerator, you'll get something that you will cancel ^_^

OpenStudy (lgbasallote):

you can either divide...or factor out the numerator then cancel

Parth (parthkohli):

Also state that x cannot be -2.

OpenStudy (lgbasallote):

x^2 - 3x - 10 = x^2 - 5x + 2x - 10 does that help?

Parth (parthkohli):

Yes, now factor by grouping.

OpenStudy (anonymous):

so would it be x – 5; where x = 5

OpenStudy (lgbasallote):

i mean rewrite x^2 -3x - 10 as \[\large x^2 - 5x + 2x - 10\]

OpenStudy (lgbasallote):

where x = 5 where did you get that? o.O

OpenStudy (anonymous):

that is one of the options to choose from

Parth (parthkohli):

Correction, \(x \neq 5\)

OpenStudy (lgbasallote):

oh well then yeah it is

Parth (parthkohli):

I see that x cannot be -2.

OpenStudy (anonymous):

ok i was just making sure thank u

OpenStudy (lgbasallote):

but unless there is an equal 0 somewhere i dont think that should be a condition

Parth (parthkohli):

Hmm you're welcome

Parth (parthkohli):

Can you tell me what do you get when you factor the numerator?

OpenStudy (anonymous):

no there is no zero thanks again guys, is it ok if I post more questions i dont understand well

OpenStudy (anonymous):

yes there is a x -2

OpenStudy (lgbasallote):

post in new question...and i have to go so @ParthKohli will be entertaining you

Parth (parthkohli):

So then x cannot be -2.

OpenStudy (anonymous):

yes

OpenStudy (lgbasallote):

x - 5 where x = 5 is good enough if there's a zero ^_^

Parth (parthkohli):

Lol yes.

Parth (parthkohli):

If there's a zero then that value is invalid.

OpenStudy (anonymous):

ok thank you i think i understand the simplifying process now if not I will just ask u guys Thank you!

Parth (parthkohli):

You are welcome, clear if any confusion ^_^

Parth (parthkohli):

You can close the question now.

Parth (parthkohli):

And post a new one if needed.

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