Mathematics
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OpenStudy (anonymous):
Please help Simplify:
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OpenStudy (anonymous):
Parth (parthkohli):
Try to factor the numerator, you'll get something that you will cancel ^_^
OpenStudy (lgbasallote):
you can either divide...or factor out the numerator then cancel
Parth (parthkohli):
Also state that x cannot be -2.
OpenStudy (lgbasallote):
x^2 - 3x - 10 = x^2 - 5x + 2x - 10
does that help?
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Parth (parthkohli):
Yes, now factor by grouping.
OpenStudy (anonymous):
so would it be x – 5; where x = 5
OpenStudy (lgbasallote):
i mean rewrite x^2 -3x - 10 as \[\large x^2 - 5x + 2x - 10\]
OpenStudy (lgbasallote):
where x = 5 where did you get that? o.O
OpenStudy (anonymous):
that is one of the options to choose from
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Parth (parthkohli):
Correction, \(x \neq 5\)
OpenStudy (lgbasallote):
oh well then yeah it is
Parth (parthkohli):
I see that x cannot be -2.
OpenStudy (anonymous):
ok i was just making sure thank u
OpenStudy (lgbasallote):
but unless there is an equal 0 somewhere i dont think that should be a condition
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Parth (parthkohli):
Hmm you're welcome
Parth (parthkohli):
Can you tell me what do you get when you factor the numerator?
OpenStudy (anonymous):
no there is no zero thanks again guys, is it ok if I post more questions i dont understand well
OpenStudy (anonymous):
yes there is a x -2
OpenStudy (lgbasallote):
post in new question...and i have to go so @ParthKohli will be entertaining you
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Parth (parthkohli):
So then x cannot be -2.
OpenStudy (anonymous):
yes
OpenStudy (lgbasallote):
x - 5 where x = 5 is good enough if there's a zero ^_^
Parth (parthkohli):
Lol yes.
Parth (parthkohli):
If there's a zero then that value is invalid.
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OpenStudy (anonymous):
ok thank you i think i understand the simplifying process now if not I will just ask u guys Thank you!
Parth (parthkohli):
You are welcome, clear if any confusion ^_^
Parth (parthkohli):
You can close the question now.
Parth (parthkohli):
And post a new one if needed.