Question

please help:)

Answer 1

@UnkleRhaukus Plz help.

Answer 2

Please see http://openstudy.com/updates/4fc4daa3e4b0964abc873531

Answer 3

I want to say that in my previous question figure was different from this, but these are depicting the different. What is this?

Answer 4

well the arrow directly to the left of the positive charge is pointing out as expected, right?, (not like the dipole in the external field)

Answer 5

I didn't understand. I wanna say that in previous question arrow was radially inward at (+)ve charge but now is radially outwards. Why?

Answer 6

At right side:)

Answer 7

This one is correct.
Yesterdays's was a mistake.

Answer 8

The is no external field present in this diagram, in the other diagram the dipole was in an external field

Answer 9

There was no external field in yesterday's picture, only a mistake in the way the arrow was pointed in one of the lines.

Answer 10

I m having confusion becoz of different comments about the question:(
would u please give me proof with a text or something.

Answer 11

@experimentX & @egenriether Plz help:)

Answer 12

but its a physics question .I have put it in chemistry section by mistake.@experimentX

Answer 13

@experimentX

Answer 14

Yesterday's picture did not mention the presence of an external field.

Field to the left of +q must point left, because field acted by +q is greater than field acted by -q (because +q is nearer than -q)

So the action of +q wins out and total field is to the left of the picture.

Answer 15

k! thanx I got this.