log(4096) as a fraction
3.6123599/1
but as a fraction what would that be
?=log(64)2
4^20* (1/128^4)
I just tried that and it was not correct...it keeps saying it is a fraction
that is a fraction.... hmmm
can you explain how to get it...
There are plenty of ways to write something as a fraction... Is this under a specific topic on Logarithms like Change of Base?
It says to evaluate the equation without using a calculator...well I'm kind of cheating because I didn't understand the calculator and I'm on this trying to get help because I'm stuck :(
like in the example it says log(81)3=12/4...but I don't know how to get the answer to this one
what is the base of the logarithm?
64^y=2
\(\huge 64^y=2\) Shoudl be written as \(\large log_{64}2=y\) I think your mistake was to square 64 like this \(\large \log64^2\)
Then get \(\large log(4096)\) Right method to do it is \(\large log_{64}2=y=\frac{1}{6}\)
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