What fraction of the rectangle is shaded? Write your answer as a rational expression in simplified form.
How do you find the area of the triangle?
i actually don't rememeber the formula
Area of a triangle = (base*height)/2 A = (bh)/2 Does that help?
ok and how do i do that with letters?
First calculate the area of the triangle A = (bh)/2 A = (x*2)/2 A = 2x/2 A = x So the area of the triangle is x square units. Making sense so far?
yes
Now calculate the area of the rectangle A = LW A = (x+2)x A = x^2+2x So the area of the rectangle is x^2+2x square units.
So what's next?
ummm i have no idea im trying to follow
The next step is to divide the area of the triangle into the area of the rectangle, so... (Area of triangle)/(Area of rectangle) = (x)/(x^2+2x) Now simplify (x)/(x^2+2x) (x)/(x(x+2)) 1/(x+2) So the fraction that's shaded is 1/(x+2)
This fraction may be a bit odd, but say x is 2 This would mean that the fraction that's shaded is 1/(x+2) = 1/(2+2) = 1/4 So when x = 2, the shaded triangle takes up a quarter of the rectangle
can u help mye with my next question?>
sure
((4x+12)/^2-2x)) * ((x)/(6x+18))
is it ((4x+12)/(x^2-2x)) * ((x)/(6x+18)) ?
Think you meant to say x^2 instead of ^2
of yes
((4x+12)/(x^2-2x))*((x)/(6x+18)) ((4x+12)*(x))/((x^2-2x)*(6x+18)) (x(4x+12))/((x^2-2x)*(6x+18)) (x(4x+12))/(x(x-2)*(6x+18)) (4x(x+3))/(x(x-2)*(6x+18)) (4x(x+3))/(x(x-2)*6(x+3)) (4x(x+3))/(6x(x-2)(x+3)) (2)/(3(x-2)) (2)/(3x-6) So the final answer is \[\Large \frac{2}{3x-6}\]
a^2 = 5a + 4 / a^3 * a^2 + 3a = 2 / a^2 - 2a
are those equal signs supposed to be + signs?
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