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OpenStudy (anonymous):
OpenStudy (anonymous):
i am confused
OpenStudy (anonymous):
first multiply the stuff in the parentheses---- you would get \[3(2k ^{2}+5k-3)\div2\] from that you simply mulitply out the 3 and that would be your answer
OpenStudy (anonymous):
how would you mulitply out the 3
OpenStudy (anonymous):
\[6k ^{2}+15k-9\div 2\] would be your answer
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OpenStudy (anonymous):
just multiply each number in the parentheses by 3...
OpenStudy (anonymous):
i dd that and got the same answer but that is not in the answer list like the A,B,C,D are different than that answer
OpenStudy (anonymous):
which is why i am confused
OpenStudy (anonymous):
a.
OpenStudy (anonymous):
b.
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OpenStudy (anonymous):
c.(k + 3)(3k + 2)
d.(3k + 1)(2k + 3)
OpenStudy (anonymous):
so now what?
OpenStudy (anonymous):
im sorry to bother u i jus treally need help onn this question
OpenStudy (anonymous):
hold up b is the same thing as the question
OpenStudy (anonymous):
o sorry hold up
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OpenStudy (anonymous):
OpenStudy (anonymous):
uh bro still the same thing....
OpenStudy (anonymous):
O i am so STUPID THIS is the question!!!
OpenStudy (anonymous):
are you still there im so sorry for the misunderstanding i though i was posting the right question....
OpenStudy (anonymous):
yeah idk about this the answer i got was (12k^3+38k^2+2K-12) all over 4k-2
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OpenStudy (anonymous):
no...thats not in the options Thanks dude for helping