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Mathematics 17 Online
OpenStudy (anonymous):

Please HELP!!!

OpenStudy (anonymous):

OpenStudy (anonymous):

i am confused

OpenStudy (anonymous):

first multiply the stuff in the parentheses---- you would get \[3(2k ^{2}+5k-3)\div2\] from that you simply mulitply out the 3 and that would be your answer

OpenStudy (anonymous):

how would you mulitply out the 3

OpenStudy (anonymous):

\[6k ^{2}+15k-9\div 2\] would be your answer

OpenStudy (anonymous):

just multiply each number in the parentheses by 3...

OpenStudy (anonymous):

i dd that and got the same answer but that is not in the answer list like the A,B,C,D are different than that answer

OpenStudy (anonymous):

which is why i am confused

OpenStudy (anonymous):

a.

OpenStudy (anonymous):

b.

OpenStudy (anonymous):

c.(k + 3)(3k + 2) d.(3k + 1)(2k + 3)

OpenStudy (anonymous):

so now what?

OpenStudy (anonymous):

im sorry to bother u i jus treally need help onn this question

OpenStudy (anonymous):

hold up b is the same thing as the question

OpenStudy (anonymous):

o sorry hold up

OpenStudy (anonymous):

OpenStudy (anonymous):

uh bro still the same thing....

OpenStudy (anonymous):

O i am so STUPID THIS is the question!!!

OpenStudy (anonymous):

are you still there im so sorry for the misunderstanding i though i was posting the right question....

OpenStudy (anonymous):

yeah idk about this the answer i got was (12k^3+38k^2+2K-12) all over 4k-2

OpenStudy (anonymous):

no...thats not in the options Thanks dude for helping

OpenStudy (anonymous):

yeah im sorry ;(

OpenStudy (anonymous):

its fine you helped so much :D

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