Mathematics
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OpenStudy (anonymous):
Find the perimeter of this trapezoid.
A(2, 1), B(6, 5), C(3, 5), D(1, 3)
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OpenStudy (mertsj):
Do you know the distance formula?
Parth (parthkohli):
Use the distance formula for all the vertices and add them up.
OpenStudy (anonymous):
no
OpenStudy (mertsj):
I will demonstrate one time and then you can practice.
OpenStudy (anonymous):
I mean, I don't know how to use it for this..
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OpenStudy (anonymous):
@Mertsj thanks
Parth (parthkohli):
\(\Large \color{MidnightBlue}{\Rightarrow D = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2} }\)
OpenStudy (anonymous):
what about perimeter?
OpenStudy (anonymous):
is that going to be the same as diameter for this?
Parth (parthkohli):
You add up the distances of all the lines.
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OpenStudy (mertsj):
Choose two of the given points and plug into the distance formula.
OpenStudy (mertsj):
Start with A and B
Parth (parthkohli):
Sketch it, then see all the vertices. Apply the distance formula for all lines and then add the distances to get the perimeter.
OpenStudy (mertsj):
That will give you the length of side AB.
Parth (parthkohli):
@Mertsj is a perfect teacher, I'll let him continue
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OpenStudy (anonymous):
I think he left!
OpenStudy (anonymous):
alright.. sketching..
OpenStudy (mertsj):
\[AB=\sqrt{(6-2)^2+(5-1)^2}=\sqrt{16+16}=4\sqrt{2}\]
Parth (parthkohli):
@rokotherodent did you understand?
OpenStudy (mertsj):
Now you try BC
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OpenStudy (anonymous):
A little bit..
OpenStudy (mertsj):
And enough of this talk about diameter. Diameter is a characteristic of a circle. We're dealing with a trapezoid here.
OpenStudy (anonymous):
@ParthKohli I'm a little confused..
OpenStudy (anonymous):
Thanks @Mertsj because I wanted perimieter
Parth (parthkohli):
I may help you understand. Where are you confused btw?
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OpenStudy (anonymous):
well, I've drawn the trapezoid.. but then
OpenStudy (mertsj):
So find the length of BC. It's an easy one because 5-5=0
Parth (parthkohli):
Think about the distance between two points by using the distance formula.
OpenStudy (anonymous):
what do I need? Do I need AB, BC, CD, and thats all?
Parth (parthkohli):
When you add the lengths of all sides, you get the perimeter.
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OpenStudy (mertsj):
Remember that perimeter is the distance around. So find the length of each side and add them together.
Parth (parthkohli):
Trapezoid = four sides
OpenStudy (anonymous):
so BC = sqrt 9 (3)?
OpenStudy (mertsj):
\[BC=\sqrt{(6-3)^2+(5-5)^2}=\sqrt{3^2+0^2}=\sqrt{9}=3\]
Parth (parthkohli):
(6,5)(3,5)
\(\Large \color{MidnightBlue}{\Rightarrow \sqrt{(6 - 3)^2 + 0^2} }\)
\(\Large \color{MidnightBlue}{\Rightarrow \sqrt{3^2} }\)
\(\Large \color{MidnightBlue}{\Rightarrow 3 }\)
Am I correct?
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OpenStudy (anonymous):
Yes, you both are!
OpenStudy (anonymous):
This is what I have..
Parth (parthkohli):
Can you do it now?
OpenStudy (anonymous):
Now lastly, I have one more question: the blank has 6 sqrt _
OpenStudy (anonymous):
do I just put 3 in that blank then?
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Parth (parthkohli):
You add the lengths of all sides. Remember.
OpenStudy (mertsj):
So far we have this start:
Perimeter = AB + BC + CD + AD = 4sqrt2+3 + CD + AD
OpenStudy (mertsj):
So if we could just find CD and AD we would have it!!
OpenStudy (anonymous):
ok
Parth (parthkohli):
Yep!
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OpenStudy (anonymous):
CD is sqrt 4
OpenStudy (anonymous):
AD is sqrt 2
Parth (parthkohli):
Hmm no
OpenStudy (mertsj):
\[CD=\sqrt{(5-3)^2+(3-1)^2}=\sqrt{2^2+2^2}=\sqrt{4+4}=\sqrt{8}=2\sqrt{2}\]
OpenStudy (mertsj):
So now we have Perimeter = AB + BC+CD+AD=4sqrt2+3+2sqrt2+AD
Try AD again.
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OpenStudy (mertsj):
Follow the distance formula.
OpenStudy (anonymous):
ok
2 - 1 = 1
1 - 3 = neg. 2
Parth (parthkohli):
@Mertsj I'm 99 now ^_^
OpenStudy (mertsj):
Squaare them now.
OpenStudy (anonymous):
okay, 2 squared is 4
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Parth (parthkohli):
And square them....then find the square root
OpenStudy (mertsj):
What is 1 squared?
Parth (parthkohli):
What is \(\sqrt{1 + 4}\)?
OpenStudy (anonymous):
1 + 4 = 5
Parth (parthkohli):
Yes. Now add all the lengths.
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OpenStudy (mertsj):
Good. So AD=?
OpenStudy (anonymous):
sqrt 5?
Parth (parthkohli):
Yes
OpenStudy (anonymous):
AD = sqrt 5
OpenStudy (anonymous):
now, adding them together..
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OpenStudy (mertsj):
Yes. Now add all four sides and remember that only similar radicals can be added.
Parth (parthkohli):
Now add the side lengths:
4sqrt2+3+2sqrt2+sqrt5
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
so that will be 6 sqrt 2 + 3 sqrt 5?
OpenStudy (mertsj):
@ParthKohli I see that you are 99 now. How did that happen so quickly?
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OpenStudy (mertsj):
Well but, I don't think you should change 3 + sqrt5 to 3 TIMES sqrt5, do you?
Parth (parthkohli):
Result of hard work from the day I joined the site aka 22 April lol
OpenStudy (anonymous):
ok I agree @Mertsj
OpenStudy (anonymous):
I think that the final answer will be: 6 sqrt 2 + sqrt 5 + 3
OpenStudy (mertsj):
So why don't we just leave it 6sqrt2+3+sqrt5 since there are no other like terms that can be added.
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OpenStudy (anonymous):
Well, I thought that we could in fact leave it at that.
OpenStudy (mertsj):
And you are correct and now we know how far it is around that trapezoid.!!!
Parth (parthkohli):
Yes, you could. Unlike terms.
Parth (parthkohli):
Finally done...ahh
OpenStudy (anonymous):
Thanks to both! I appreciate your help!
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Parth (parthkohli):
you're welcome :D
OpenStudy (mertsj):
yw and we hope you have learned a lot.
Parth (parthkohli):
Can you do the rest?
OpenStudy (anonymous):
I have! I have an identical problem that I'll work myself! :D @ParthKohli
Parth (parthkohli):
Sure....! If you have any confusion then contact me or Mertsj.
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OpenStudy (mertsj):
Excellent. And then if you want someone to check it you have ParthKohli's number.
OpenStudy (anonymous):
Alrighty! thanks!