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Simplify the following expression show all of your work: x/x-4 + 6/x+4 ÷ 3/2x^2 - 32
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\[\frac{x}{x-4} + \frac{6}{x+4} ÷ \frac{3}{2x^2 - 32}\]What is the LCD of the first two terms?
x-4 & x+4?
u still here
Sorry, had to make dinner for the family. Yes, that is LCD so expression would now be\[\frac{x(x+4)+6(x-4)}{(x-4)(x+4)}\times \frac{2(x^2-16)}{3}\]Do you know what the factors of (x^2-16) are?
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Hint:\[x^2-c^2=(x+c)(x-c)\]
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